If anyone knows this can you please help i have about an hour left to submit this (:Find the area of a triangle with the given vertices.Part I: Graph the following points on the coordinate grid below.(1, -3), (3, -1), (5, -3)Part II: Find the area of the triangle. Show your work.

Answer: Part 1 : Figure show the graph of triangle Part 2 : The area of triangle is 4 sqaure unitsStep-by-step explanation:Given points A(1, -3), B(3, -1) and C(5, -3) make triangle.Part 1:Figure show the graph of triangle with A(1, -3), B(3, -1) and C(5, -3)  as vertices.Part 2: Find the area of the triangle. The area of triangle is given by A=[tex]\frac{(Base)(height)}{2}[/tex]From figure, Take base as length of ACLength of line is given by L=[tex]\sqrt{(X1-X2)^{2}+(Y1-Y2)^{2} }[/tex]Now, Base = length of ACBase =[tex]\sqrt{(X1-X2)^{2}+(Y1-Y2)^{2} }[/tex]         =[tex]\sqrt{(1-5)^{2}+((-3)-(-3))^{2}}[/tex]         =[tex]\sqrt{(-4)^{2}+(0)^{2}}[/tex]         =[tex]\sqrt{16}[/tex]         =4unitsand Height as difference of y-component of point A and point BHeight = (y of component of point B)- (y of component of point A)            = (-1)- (-3)            = 2unitsTherefore, The area of triangle is given by A=[tex]\frac{(Base)(height)}{2}[/tex]A=[tex]\frac{(4)(2)}{2}[/tex]A=4 sqaure units