Look at the right triangle ABC: Right triangle ABC has a right angle at B. Segment BD meets segment AC at a right angle. A student made the following chart to prove that AB2 + BC2 = AC2:First one is the Statement and the second one is the Justification1. Triangle ABC is similar to triangle BDC 1. Angle ABC = Angle BDC and Angle BCA = Angle BCD2. BC2 = AC • DC 2. BC ÷ DC = BC ÷ AC because triangle ABC is similar to triangle BDC3. Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle ADB and Angle BAC = Angle BAD4. AB2 = AC • AD 4. AB ÷ AD = AC ÷ AB because triangle ABC is similar to triangle ADB5. AB2 + BC2 = AC • AD + AC • DC = AC (AD + DC) 5. Adding Statement 1 and Statement 26. AB2 + BC2 = AC2\6. AD + DC = ACWhat is the first incorrect justification?