Three dice are rolled. Find the probability of obtaining a sum greater than 5

There are a total of $$6^3=216$$ possible outcomes when rolling three dice. The only way to obtain a sum less than or equal to 5 is to roll three 1s, three 2s, three 3s, or two 1s and one 4. There are 4 of these outcomes, so the probability of obtaining a sum less than or equal to 5 is 4/216. Therefore, the probability of obtaining a sum greater than 5 is 1− 4/216 = 212/216