Sixty students were given a history exam. Their scores are shown below, sorted from smallest to largest16 28 29 34 3537 37 39 39 4041 42 43 43 4647 53 65 70 7273 74 74 74 7475 76 77 78 7878 79 79 79 7979 80 81 81 8181 81 82 82 8282 82 82 83 8383 83 83 83 8586 87 87 88 941) Compute the 5-number summary for this data:

Answer:The 5-number summary refers to:Minimum = 16First Quartile (Q1) = 46.5Median = 78Third Quartile (Q3) = 82Maximum = 94See the explanation section for detailsStep-by-step explanation:The 5-number summary refers to:Minimum = 16First Quartile (Q1) = 46.5Median = 78Third Quartile (Q3) = 82Maximum = 941. Minimum is 16. Since the number is already arranged in ascending order.2. First Quartile is defined as the median of the lower half.   [tex]Q1 = \frac{46 + 47}{2}  = 46.5[/tex]46 and 47 are the median of the first half of the score, that is 15th and 16th score.3. Median is the sum of the 30th and 31th score divide by two, which is 78 and 78. Median = [tex]\frac{78 + 78}{2}  = \frac{156}{2}  = 78[/tex]4. Third quartile is define as the median of the upper half.    [tex]Q3 = \frac{82 + 82}{2}  = 82[/tex]82 and 82 are the median of the upper half of the score, that is 45th and 46th score.5. Maximum is 94.