solve by eliminating 1/3x-y=-3 x+5/2y=2

Question
Answer:
$$\frac{1}{3}x-y=-3,x+\frac{5}{2}y=2$$
$$\frac{1}{3}x-y=-3,\frac{1}{3}x+\frac{1}{3}\times \left(\frac{5}{2}\right)y=\frac{1}{3}\times 2$$
$$\frac{1}{3}x-y=-3,\frac{1}{3}x+\frac{5}{6}y=\frac{2}{3}$$
$$\frac{1}{3}x-\frac{1}{3}x-y-\frac{5}{6}y=-3-\frac{2}{3}$$
$$-y-\frac{5}{6}y=-3-\frac{2}{3}$$
$$-\frac{11}{6}y=-3-\frac{2}{3}$$
$$-\frac{11}{6}y=-\frac{11}{3}$$
$$y=2$$
$$x+\frac{5}{2}\times 2=2$$
$$x+5=2$$
$$x=-3$$
$$x=-3,y=2$$
solved
general 11 months ago 2014