Solve for x in the equation x^2+2x+1=17

Answer:x= (-1+ √17) or (-1-√17)Step-by-step explanation:In this question, we have to solve for x from the given equation x² +2x+1 =17Now, the equation can be rearranged to x² +2x -16 =0.Here we can not apply the process of factorization to get the value of x.Hence, we will use the Shridhar Acharya formula to solve the value of x.{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as x=[-b±√(b²-4ac)]/2a }Hence, in this case, the solution for x will be x=[tex]\frac{-2+\sqrt{2^{2}-4(1)(-16) } }{2(1)} or  \frac{-2-\sqrt{2^{2}-4(1)(-16) } }{2(1)}[/tex]⇒ x=[tex]\frac{-2+2\sqrt{17} }{2} or  \frac{-2-2\sqrt{17} }{2}[/tex]⇒ x= (-1+ √17) or (-1-√17) (Answer)