Solve the following system. y = (1/2)x 2 + 2x - 1 and 3x - y = 1 The solutions are ( )and ( ) (remember to include the commas)

Answer:x=0, 2. y=-1, 5.Step-by-step explanation:y=(1/2)x^2+2x-13x-y=1---------------------3x-y=1y=3x-1-----------(1/2)x^2+2x-1=3x-1(1/2)x^2+2x-3x-1-(-1)=0(1/2)x^2-x-1+1=0(1/2)x^2-x=0factor out the xx[(1/2)x-1]=0zero property,x=0, (1/2)x-1=0-------------------(1/2)x-1=01/2x=0+11/2x=1x=1/(1/2)=(1/1)(2/1)=2/1=2-----------------------------------x=0, x=2-------------y=(1/2)(0)^2+2(0)-1=0+0-1=-1-------------y=3(0)-1=0-1=-1-----------------------y=(1/2)(2)^2+2(2)-1=(1/2)(4)+4-1=4/2+4-1=2+4-1=6-1=5----------------------y=3(2)-1=6-1=5