The function f(x) = x2 − 12x + 5 written in vertex form is f(x) = (x − 6)2 − 31. What are the coordinates of the vertex?(6, 31)(−6, 31)(6, −31)(−6, −31)

[tex]\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\ -------------------------------\\\\ f(x)=1(x-\stackrel{h}{6})^2\stackrel{k}{-31}\qquad \qquad vertex~(6,-31)[/tex]