The surface areas of two similar figures are 25 in2 and 36 in2. If the volume of the smaller figure is 250 in3, what is the volume of the larger figure? a. 360 in3 b. 300 in3 c. 432 in3 d. 145 in3

Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is [tex]25in^{2}[/tex], and its volume is [tex]250in^{3}[/tex]. We also know that the area of the larger figure is [tex]36in^{2}[/tex]; since we don't now its volume, lets represent it with [tex]X[/tex]:
[tex] \frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} [/tex] 
[tex] \frac{25}{36} = \frac{250}{X} [/tex]
[tex]X= \frac{(250)(36)}{25} [/tex]
[tex]X=360[/tex]

We can conclude that the volume of the larger figure is [tex]360in^{3}[/tex]; therefore, the correct answer is a.