point Q lies in the interior of angle RST. If m<RST=125 degrees, m<RSQ=4x-7, m<QST=11x+12, then find x.A) x=5B) x=8C) x=6D) x=4
Question
Answer:
You have known that: <RST=<RSQ+<QSTSo we have 125°= (4x-7)+ (11x+12)
and 125°= 4x-7°+ 11x+12°
or 125°= 15x+5°
and 15x=125°-5°
and 15x=120°
By dividing by 15 we have x=120°:15= 8°
Have fun with x=8°
solved
general
11 months ago
4708