Use sigma notation to represent the sum of the first six terms of the following sequence: −10, −13, −16, …the summation from n equals one to 6 of quantity negative 10 plus 3 times nthe summation from n equals one to 6 of quantity negative 7 minus 10 times n the summation from n equals one to 6 of quantity negative 7 minus 3 times nthe summation from n equals one to 6 of quantity negative 7 plus 3 times n

Answer:"the summation from n equals one to 6 of quantity negative 7 minus 3 times n"Step-by-step explanation:General term of an arithmetic sequence:[tex]a_n=a_1+(n-1)r[/tex]Where [tex]a_1[/tex] is the first termn is the number of termsr is the common differenceThe value of r can be found by subtracting two consecutive values[tex]r=a_2-a_1=-13+10=-3[/tex]Then[tex]a_n=-10+(n-1)(-3)=-7-3n[/tex]If we want to sum the first six terms of the sequence, we must find[tex]\sum_{n=1}^{n=6}(-7-3n)[/tex]The correct option is"the summation from n equals one to 6 of quantity negative 7 minus 3 times n"