What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = x = x = x = x =
Question
Answer:
x²+5x+5 has zeroes given by x=(-5±√25-20)/2=(-5±√5)/2=-1.3820 and -3.6180.In simplest radical form the zeroes are -5/2+√5/2 and -5/2-√5/2.
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