Which function in vertex form is equivalent to f(x) = 4 + x2 – 2x? f(x) = (x – 1)2 + 3 f(x) = (x – 1)2 + 5 f(x) = (x + 1)2 + 3 f(x) = (x + 1)2 + 5

The vertex form which is equivalent to the provided quadratic function of variable x is (x-1)²+3.What is the vertex form of parabola?Vertex form of parabola is the equation form of quadratic equation, which is used to find the coordinate of vertex points at which the parabola crosses its symmetry.The standard equation of the vertex form of parabola is given as,[tex]y=a(x-h)^2+k[/tex]Here, (h, k) is the vertex point.The function given in the problem is,[tex]f(x) = 4+x^2 - 2x\\f(x) = x^2 - 2x+4[/tex]Add and subtract (-1)² in the above function,[tex]f(x) = x^2 - 2x+4+(-1)^2-(-1)^2\\f(x) = x^2 - 2x+(-1)^2+4-1[/tex]Use the formula of whole square,[tex]f(x)=(x-1)^2+3[/tex]This is the required vertex form.Hence, the vertex form which is equivalent to the provided quadratic function is (x-1)²+3.Learn more about the vertex form of the parabola here;