Which is the equation of a parabola with focus (0, 5) and directrix y= -5?
Question
Answer:
Answer:Step-by-step explanation:Let P(x,y) be any point on the parabola.focus S (0,5)Directrix y=-5or y+5=0let M be foot of perpendicular from P(x,y) on directrix.SP=[tex]SP=\sqrt{(x-0)^2+(y-5)^2}\\ PM=\frac{y+5}{\sqrt{1} } =y+5[/tex]SP=PMSP²=PM²(x-0)²+(y-5)²=(y+5)²x²=(y+5)²-(y-5)²or x²=y²+10y+25-(y²-10y+25)x²=y²+10y+25-y²+10y-25x²=20y
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general
11 months ago
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