WILL GIVE 99 POINTS IF ANSWERED ASAP PLEASE

Answer:Part A1.  Perimeter of the outside edges = 24 inches2.  One possibility is: length = 8 in. and width = 8 in.second possibility is: length = 16 in. and width = 4 in.3.  Area of the wood portion = 11 [tex]inches^{2}[/tex]4.  New dimensions are:Length = 17.5 ft.Width = 12.5 ft.Part BArea of the picture = 24 [tex]inches^{2}[/tex]Area of the frame = 35 [tex]inches^{2}[/tex]Step-by-step explanation:Part A1.  Perimeter of the outside edges = 2(length + width)= 2(7 + 5)= 2(12)= 24 inches
2.  If the area of the frame was 64 [tex]inches^{2}[/tex], then the two possible dimensions are:8 × 8 and 16 × 4i.e., one possibility is: length = 8 in. and width = 8 in.second possibility is: length = 16 in. and width = 4 in.
3.  Area of the wood portion = Area of the frame - Area of the picture= (5 × 7) - (4 × 6)= 35 - 24= 11 [tex]inches^{2}[/tex]
4.  The scale factor is:1 in. = 2.5 ft.So, its length = 7 in. = 7(2.5) = 17.5 ft.width = 5in. = 5(2.5) = 12.5 ft.
Part B:Length of the picture = 6in.Width of the picture = 4 in.Area of the picture = Length × Width= 6 × 4= 24 [tex]inches^{2}[/tex]Length of the frame = 7in.Width of the frame = 5 in.Area of the frame = 7 × 5 = 35 [tex]inches^{2}[/tex]