Write the simplest polynomial function with the given roots 2i, square root of 3, and 4

Answer:y = (x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3) Possible answery = (x - 4)(x^2 + 4)(x^2 - 3)                    Possible answer
Step-by-step explanation:The simplest answer is that 2i cannot be a lone root. It must have a twin that is - 2i√3 has the same sort of rule. It cannot be a root all by itself. It also must have a twin, in this case -√3So the answer must be(x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3)      <<< Possible answerbut this can be reduced even further.(x + 2i)(x - 2i) = x^2 - x*2i + x*2i - 4i^2(x + 2i)(x - 2i) = x^2 - 4(i)^2(x + 2i)(x - 2i) = x^2  + 4.               Remember i^2 = - 1By a similar method (x - √3)(x + √3) = x^2 - 3So the polynomial is reduced to(x - 4)(x^2 + 4)(x^2 - 3)  <<<< AnswerIf this is not among your answers and the  factored form is not either, please tell me what is.