You budget $2400 for contstructing a rectangular enclosure that consists of a high surrounding fence and a lower inside fence that divides the enclosure in half. the high fence costs $8 per foot, and the low fence costs $4 per foot. find the dimensions and the maximum area of each half of the enclosure.

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Answer:
The dimensions of the rectangular enclosure are 60 feet and 75 feet and the maximum area of each half of the enclosure is 2250 feet².How to calculate the dimensions?From the information given, the cost of the higher fence is represented as:= 8(2w + 2l) = 16w + 16lThe cost of the lower fence will be 4w.The relationship between the length and width will be illustrated thus:2400 = 16w + 16l + 4l2400 = 20l + 16wDivide through by 4600 = 4l + 5wExpress l in terms of the width.l = 150 - 1.25wThe area will be:= (150 - 1.25w) × w= 150w - 1.25w²The maximum area will be where the vertex of the parabola is. They are w1 = 0 and w2 = 120.The width of the fence is 60 feet. The length will be:= 1/4(600 - 5 × 60)= 75 feetThe area of the lower fence will be:= 1/2 × 60 × 75= 2250 feet²Learn more about dimensions on:
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general 11 months ago 5079