z varies directly with x2 and inversely with y. When x = 2 and y = 4, z = 3. What is the value of z when x = 4 and y = 9?
Question
Answer:
z = (kx^2)/y -> 3 = (k(2^2))/(4) -> k=3z = (3*4^2)/9 = 16/3
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11 months ago
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