What volume of 0.20MNaClaq contains 10.0g of NaCl molar mass 58g/mol?

Answer: 0.862 LExplanation:First off, I'd like to say that I have not done many problems like this, so this could very well be wrong.So lets do dimensional analysis:\(\frac{10 g}{given} * \frac{1 mol}{58g}*\frac{1L}{0.2mol}\)This gives us 10 L / (0.2 * 58) when we cross out units. Divide and we get 0.862 L