$75,000 is invested at 5% compounded annually. Find the total amount, to the nearest cent, after 5 years.$0.02$58,033.57$569,531.25$95, 7521.12

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$75000\\ r=rate\to 5\%\to \frac{5}{100}\to &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=75000\left(1+\frac{0.05}{1}\right)^{1\cdot 5}\implies A=75000(1.05)^5[/tex]