A certain math conference has 8338 attendees. Of these individuals, 6364 are college professors, and 4407 are female. Of the college professors, 2733 are female. What is the probability that a randomly selected attendee is female or a college professor? Answers should be decimals (not percentages) correct to three decimal places.
Question
Answer:
n(female or college professors) = n(female) + n(college professors) - n(female college professors)
n(female or college professors) = 6364 + 4407 - 2733 = 8038
Probability:
$$ \frac{8038}{8338} = 0.964$$
Answer: 0.964
solved
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7 months ago
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