A weighted die, numbered one through six, has a probability of 1/4 of rolling a six. if this die is rolled three times, and each roll is independent, what is the probability of rolling at least two sixes?

Probability of  rolling no sixes = (3/4)^3  =  27/64

Probability of first one being 6 and the rest Not 6  = 1/4 * 3/4* 3/4 = 9/64

THere are 3 ways  for this to happen  so total probability of 1 six = 27/64

Therefore Probability of 2 or more sixes =   1 - 2(27/64) = 10/54  = 5/27

Answer is 5/27