complete the table to determine if wavelength varies inversely with frequency...

Answer:All requested products give the same answer, a = b = c = d = 3 [tex]10^8[/tex] therefore type "3" in each the boxes.Step-by-step explanation:You are asked to evaluate "k" (the product between wavelength and frequency) for all cases, and write your answer in scientific notation. Let's work on each of them:1) [tex]1\,*\,10^{-10}\,*\,3\,*\.10^{18}=3\,*\,10^{18-10}\,=\,3\,*\,10^8[/tex], therefore the requested value "a" (factor that multiplies [tex]10^8[/tex] is 3.2) [tex]1\,*\,10^{-1}\,*\,3\,*\.10^{9}=3\,*\,10^{9-1}\,=\,3\,*\,10^8[/tex], and again, the factor that multiplies [tex]10^8[/tex] is 3.3) [tex]600\,*\,10^{-6}\,*\,5\,*\,10^{11}=3000\,*\,10^{11-6}\,=\,3000\,*\,10^5\,=\,3\,*\,10^3\,*\,10^5\,=\,3\,*\,10^{3+5}\,=\,3\,*\,10^8[/tex]so once more the multiplicative factor your are being ask to find is "3".4) [tex]4\,*\,10^{-7}\,*\,7.5\,*\,10^{14}=30\,*\,10^{14-7}\,=\,3\,*\,10\,*\,10^{7}\,=\,3\,*\,10^{1+7}\,=\,3\,*\,10^8[/tex] this shows that even the last product results in the same value for the factor "3" that multiplies [tex]10^8[/tex].For your information, this repeated result that we are getting by making the product of the wavelength of a type of radiation and its frequency is the value of the speed of light in vacuum in km/s.