The number of punctures in the tires of a certain commercial vehicle has a Poisson distribution with a mean of 0.3 per 50,000 kilometers. a) Find the expected number of punctures in 250,000 km. vehicle tours.
Question
Answer:
Answer:
1.5
Solution:
$$ 250000\times\frac{0.3}{50000}=1.5 $$
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