Factor 3x^2 − 6x − 9 completely. A. 3(x − 1)(x + 3) B. 3(x + 1)(x − 3) C. (3x + 1)(x − 3) D. (3x -1)(x + 3)

I'm pretty sure the answer is B. First you take out a factor of three then the 6 becomes a 3 meaning that the answer has to add to negative two.