Given the quadratic function f(x)=2x2-3x-3. Determine the x-intercepts

Question
Answer:
$x_{1,2}=\frac{-(-3)\pm \sqrt{(-3)^{2}-4\cdot 2(-3)}}{2\cdot 2}$
$x_{1,2}=\frac{-(-3)\pm \sqrt{33}}{2\cdot 2}$
$x_{1}=\frac{-(-3)+\sqrt{33}}{2\cdot 2},x_{2}=\frac{-(-3)-\sqrt{33}}{2\cdot 2}$
$=\frac{3+\sqrt{33}}{4}$
$=\frac{3-\sqrt{33}}{4}$
$x=\frac{3+\sqrt{33}}{4},x=\frac{3-\sqrt{33}}{4}$
solved
general 11 months ago 463