HELP ASAP! What is the value of θ for the acute angle in a right triangle?sin(θ)=cos(48°)Enter your answer in the box

sin(θ) = cos(48°)
sin(θ) = 0.6691
θ = arcsin (0.6691)
θ = 42°

** for these types of problems, get familiar with the inverse functions on your calculator:
[tex]arcsin = { \sin}^{ - 1} \\ arccos = { \cos}^{ - 1} \\ arctan = { \tan}^{ - 1} [/tex]